(20/(x^2-4))-(5/(x-2))=4/(x+2)

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Solution for (20/(x^2-4))-(5/(x-2))=4/(x+2) equation:


D( x )

x+2 = 0

x-2 = 0

x^2-4 = 0

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x^2-4 = 0

x^2-4 = 0

1*x^2 = 4 // : 1

x^2 = 4

x^2 = 4 // ^ 1/2

abs(x) = 2

x = 2 or x = -2

x in (-oo:-2) U (-2:2) U (2:+oo)

20/(x^2-4)-(5/(x-2)) = 4/(x+2) // - 4/(x+2)

20/(x^2-4)-(5/(x-2))-(4/(x+2)) = 0

20/(x^2-4)-5*(x-2)^-1-4*(x+2)^-1 = 0

20/(x^2-4)-5/(x-2)-4/(x+2) = 0

(20*(x-2)*(x+2))/((x^2-4)*(x-2)*(x+2))+(-5*(x^2-4)*(x+2))/((x^2-4)*(x-2)*(x+2))+(-4*(x^2-4)*(x-2))/((x^2-4)*(x-2)*(x+2)) = 0

20*(x-2)*(x+2)-5*(x^2-4)*(x+2)-4*(x^2-4)*(x-2) = 0

10*x^2-5*x^3-4*x^3+8*x^2+20*x+16*x-40-32 = 0

18*x^2-9*x^3+36*x-72 = 0

18*x^2-9*x^3+36*x-72 = 0

9*(2*x^2-x^3+4*x-8) = 0

2*x^2-x^3+4*x-8 = 0

{ 1, -1, 2, -2, 4, -4, 8, -8 }

1

x = 1

2*x^2-x^3+4*x-8 = -3

1

-1

x = -1

2*x^2-x^3+4*x-8 = -9

-1

2

x = 2

2*x^2-x^3+4*x-8 = 0

2

x-2

4-x^2

2*x^2-x^3+4*x-8

x-2

x^3-2*x^2

4*x-8

8-4*x

0

4-x^2 = 0

DELTA = 0^2-(-1*4*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)+0)/(-1*2) or x = (0-16^(1/2))/(-1*2)

x = -2 or x = 2

x in { -2, 2, 2}

9*(x+2)*(x-2)^2 = 0

(9*(x+2)*(x-2)^2)/((x^2-4)*(x-2)*(x+2)) = 0

(9*(x+2)*(x-2)^2)/((x^2-4)*(x-2)*(x+2)) = 0 // * (x^2-4)*(x-2)*(x+2)

9*(x+2)*(x-2)^2 = 0

( x+2 )

x+2 = 0 // - 2

x = -2

( x-2 )

x-2 = 0 // + 2

x = 2

x in { -2}

x in { 2}

x belongs to the empty set

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